Hello,

I am trying to pass an XmlDocument's DocumentElement as a parameter to
an XSL template. I'm doing so because I want to process two XML
documents in the XSL template, and output one XML document as a result.


My results yield blanks for the second XML file. Note that I've tried
using a variable instead of a parameter, and that works. But I don't
want to use the document('Xml2.xml') logic in my XSL template.

Here is my code.

Dim m_xmlDom1 As XmlDocument
Dim m_xmlDom2 As XmlDocument

'Create document 1
m_xmlDom1 = New XmlDocument
m_xmlDom1.Load("Xml1.xml")
'Create document 2
m_xmlDom2 = New XmlDocument
m_xmlDom2.Load("Xml2.xml")
' Create the XslTransform and load the stylesheet.
Dim xslt As XslTransform = New XslTransform
xslt.Load("TwoXmlFiles.xsl")
' Create an XsltArgumentList.
Dim xslArg As XsltArgumentList = New XsltArgumentList
' Add parameters
xslArg.AddParam("xml2", "", m_xmlDom2.DocumentElement)

'Create an XmlTextWriter to handle the output, but put it in a
string.
Dim sb As StringBuilder = New StringBuilder
Dim sw As StringWriter = New StringWriter(sb)
Dim xw As XmlTextWriter = New XmlTextWriter(sw)

'Transform the file.
Try
xslt.Transform(m_xmlDom1.CreateNavigator(), xslArg, xw,
Nothing)

Catch ex As Exception
MessageBox.Show(ex.Message)
End Try
'Get the output
MessageBox.Show(sb.ToString())
'Close the xml text writer
xw.Close()

Here is Xml1.xml.

<?xml version="1.0" encoding="UTF-8"?>
<CONTACTS>
<CONTACT>
<NAME>John Smith</NAME>
</CONTACT>
</CONTACTS>

Here is Xml2.xml.

<?xml version="1.0"?>
<PROPERTIES>
<PROPERTY>
<NAME>1600 West York Ave., York, MN 21838</NAME>
</PROPERTY>
</PROPERTIES>

Here is my Xsl template.

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">

<xslaram name="xml2" select="."/>

<xsl:template match="/">
<xsl:apply-templates select="CONTACTS/CONTACT"/>
</xsl:template>

<xsl:template match="CONTACT">
<xsl:value-of select="NAME"/>
<xsl:value-of select="count($xml2/PROPERTIES/PROPERTY)"/>
<xsl:apply-templates select="$xml2/PROPERTIES/PROPERTY"/>
</xsl:template>

<xsl:template match="PROPERTY">
<xsl:value-of select="NAME"/>
</xsl:template>

</xsl:stylesheet>

Thanks.

Rob

I've figured out the problem. You do not pass a DocumentElement to the
AddParam method. You pass an XPathNavigator as follows.

xslArg.AddParam("xml2", "", m_xmlDom2.CreateNavigator())

And there is it.


rmgalante (AT) yahoo (DOT) com wrote: