Hey,

I was wondering if i could create a program in Visual Studio 2008 with a
link to an executable of an application (like MS WORD) in it.

By pressing a button, the executable of the application should start.

I can't manage to find out the right code to do so.


Can anyone help me out?



Thanks in advance.

Stan

On 5/9/2010 11:38 AM, SDS2 wrote:

Look at System.Diagnostics.Process.Start("some path to an exe");

--
Mike

Stan,

Do you want to open a file while you're at it?

Here's what I'm doing...not sure it's the best method.

Imports Microsoft.Office.Interop

Private Sub ReportsToolStripMenuItem_Click(ByVal sender As
System.Object, ByVal e As System.EventArgs) Handles
ReportsToolStripMenuItem.Click
Dim MyAccess As Access.Application
MyAccess = GetObject("P:\Production Resources\Legal55\Reports
\Timekeeper Reports.mdb", "Access.Application")
MyAccess.Visible = True
End Sub

Patrick

On 5/10/2010 6:24 PM, Patrick A wrote:
If you just want to launch access (or word) with a given file, then you
should use:

dim p as new Process()
p.StartInfo.FileName = "somefilename.mdb" ' or "somefilename.doc"
p.StartInfo.Verb = "Open"
p.Start()

--
Mike

Isn't there a method that is able to open any path? (an application?)


"Family Tree Mike" <FamilyTreeMike (AT) ThisOldHouse (DOT) com> schreef in bericht
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The System.Diagnostics.Process.Start
works perfectly!

Thanks a lot!


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