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  #1  
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=?Utf-8?B?cnZhbmdlbGRyb3A=?=
 
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Default Exact implementation of PasswordDerivedBytes - 07-30-2007 , 05:40 AM






Hello,

We are currently running a project in which we wish to reengineer parts of
the System.Security.Cryptography namespace on a unix machine.

We discovered that the implementation of the PasswordDerivedBytes shows some
unexpected results in case the input is a 32 bytes length MD5 hash which is
iterated twice. It seems that the existing documentation on this function is
incorrect. It would be nice if we would know what exact algorithm is used to
calculate the 32 bytes version, since in theory an MD5 hash can never result
in a 32 byte length.

This is our C# code:

PasswordDeriveBytes pdb =
new PasswordDeriveBytes("secretkey",
Encoding.ASCII.getBytes("*&JHj_JHG"), "MD5", 2);

byte[] hash16bytes = pdb.getBytes(16);
byte[] hash32bytes = pdb.getBytes(32);

and results are:

For 16 bytes:

59 192 53 176 173 34 125 34 236 243 119 17 31 99 147 180

For 32 bytes:

115 229 92 88 209 121 109 87 144 35 48 70 22 39 222 198
159 230 239 240 3 64 182 168 91 39 214 244 54 200 89 222

So how is the 32 bytes result calculated?

Thanks,

rvangeldrop

Reply With Quote
  #2  
Old   
Dominick Baier
 
Posts: n/a

Default Re: Exact implementation of PasswordDerivedBytes - 07-30-2007 , 10:12 AM






Use reflector.

-----
Dominick Baier (http://www.leastprivilege.com)

Developing More Secure Microsoft ASP.NET 2.0 Applications (http://www.microsoft.com/mspress/books/9989.asp)

Quote:
Hello,

We are currently running a project in which we wish to reengineer
parts of the System.Security.Cryptography namespace on a unix machine.

We discovered that the implementation of the PasswordDerivedBytes
shows some unexpected results in case the input is a 32 bytes length
MD5 hash which is iterated twice. It seems that the existing
documentation on this function is incorrect. It would be nice if we
would know what exact algorithm is used to calculate the 32 bytes
version, since in theory an MD5 hash can never result in a 32 byte
length.

This is our C# code:

PasswordDeriveBytes pdb =
new PasswordDeriveBytes("secretkey",
Encoding.ASCII.getBytes("*&JHj_JHG"), "MD5", 2);
byte[] hash16bytes = pdb.getBytes(16);
byte[] hash32bytes = pdb.getBytes(32);
and results are:

For 16 bytes:

59 192 53 176 173 34 125 34 236 243 119 17 31 99 147 180

For 32 bytes:

115 229 92 88 209 121 109 87 144 35 48 70 22 39 222 198
159 230 239 240 3 64 182 168 91 39 214 244 54 200 89 222
So how is the 32 bytes result calculated?

Thanks,

rvangeldrop




Reply With Quote
  #3  
Old   
Dominick Baier
 
Posts: n/a

Default Re: Exact implementation of PasswordDerivedBytes - 07-30-2007 , 10:12 AM



Use reflector.

-----
Dominick Baier (http://www.leastprivilege.com)

Developing More Secure Microsoft ASP.NET 2.0 Applications (http://www.microsoft.com/mspress/books/9989.asp)

Quote:
Hello,

We are currently running a project in which we wish to reengineer
parts of the System.Security.Cryptography namespace on a unix machine.

We discovered that the implementation of the PasswordDerivedBytes
shows some unexpected results in case the input is a 32 bytes length
MD5 hash which is iterated twice. It seems that the existing
documentation on this function is incorrect. It would be nice if we
would know what exact algorithm is used to calculate the 32 bytes
version, since in theory an MD5 hash can never result in a 32 byte
length.

This is our C# code:

PasswordDeriveBytes pdb =
new PasswordDeriveBytes("secretkey",
Encoding.ASCII.getBytes("*&JHj_JHG"), "MD5", 2);
byte[] hash16bytes = pdb.getBytes(16);
byte[] hash32bytes = pdb.getBytes(32);
and results are:

For 16 bytes:

59 192 53 176 173 34 125 34 236 243 119 17 31 99 147 180

For 32 bytes:

115 229 92 88 209 121 109 87 144 35 48 70 22 39 222 198
159 230 239 240 3 64 182 168 91 39 214 244 54 200 89 222
So how is the 32 bytes result calculated?

Thanks,

rvangeldrop




Reply With Quote
  #4  
Old   
=?Utf-8?B?cnZhbmdlbGRyb3A=?=
 
Posts: n/a

Default Re: Exact implementation of PasswordDerivedBytes - 07-30-2007 , 10:42 AM



Hi Dominick,

This is obviously not the kind of answer I am expecting.

1. Can you explain me in more detail what 'reflector' is and how I can use it?

2. Maybe it is easier to give me the code inside PasswordDeriveBytes, since
with other similar situations I'm used to being helped that way. We are a
Gold Certified Partner so I was guessing I'm entitled to a more
service-oriented answer.

This answer is also very disappointing since the documentation Microsoft is
already providing on this subject is incorrect: "This class uses an extension
of the PBKDF1 algorithm defined in the PKCS#5 v2.0 standard to derive bytes
suitable for use as key material from a password. The standard is documented
in IETF RRC 2898." see also:

http://msdn2.microsoft.com/en-us/lib...vebytes.a spx

I expect you to help me explain why this incorrect and what the actual
implementation is. If this document would be correct my results would have
been different.

Regards,

rvangeldrop

"Dominick Baier" wrote:

Quote:
Use reflector.

-----
Dominick Baier (http://www.leastprivilege.com)

Developing More Secure Microsoft ASP.NET 2.0 Applications (http://www.microsoft.com/mspress/books/9989.asp)

Hello,

We are currently running a project in which we wish to reengineer
parts of the System.Security.Cryptography namespace on a unix machine.

We discovered that the implementation of the PasswordDerivedBytes
shows some unexpected results in case the input is a 32 bytes length
MD5 hash which is iterated twice. It seems that the existing
documentation on this function is incorrect. It would be nice if we
would know what exact algorithm is used to calculate the 32 bytes
version, since in theory an MD5 hash can never result in a 32 byte
length.

This is our C# code:

PasswordDeriveBytes pdb =
new PasswordDeriveBytes("secretkey",
Encoding.ASCII.getBytes("*&JHj_JHG"), "MD5", 2);
byte[] hash16bytes = pdb.getBytes(16);
byte[] hash32bytes = pdb.getBytes(32);
and results are:

For 16 bytes:

59 192 53 176 173 34 125 34 236 243 119 17 31 99 147 180

For 32 bytes:

115 229 92 88 209 121 109 87 144 35 48 70 22 39 222 198
159 230 239 240 3 64 182 168 91 39 214 244 54 200 89 222
So how is the 32 bytes result calculated?

Thanks,

rvangeldrop





Reply With Quote
  #5  
Old   
=?Utf-8?B?cnZhbmdlbGRyb3A=?=
 
Posts: n/a

Default Re: Exact implementation of PasswordDerivedBytes - 07-30-2007 , 10:42 AM



Hi Dominick,

This is obviously not the kind of answer I am expecting.

1. Can you explain me in more detail what 'reflector' is and how I can use it?

2. Maybe it is easier to give me the code inside PasswordDeriveBytes, since
with other similar situations I'm used to being helped that way. We are a
Gold Certified Partner so I was guessing I'm entitled to a more
service-oriented answer.

This answer is also very disappointing since the documentation Microsoft is
already providing on this subject is incorrect: "This class uses an extension
of the PBKDF1 algorithm defined in the PKCS#5 v2.0 standard to derive bytes
suitable for use as key material from a password. The standard is documented
in IETF RRC 2898." see also:

http://msdn2.microsoft.com/en-us/lib...vebytes.a spx

I expect you to help me explain why this incorrect and what the actual
implementation is. If this document would be correct my results would have
been different.

Regards,

rvangeldrop

"Dominick Baier" wrote:

Quote:
Use reflector.

-----
Dominick Baier (http://www.leastprivilege.com)

Developing More Secure Microsoft ASP.NET 2.0 Applications (http://www.microsoft.com/mspress/books/9989.asp)

Hello,

We are currently running a project in which we wish to reengineer
parts of the System.Security.Cryptography namespace on a unix machine.

We discovered that the implementation of the PasswordDerivedBytes
shows some unexpected results in case the input is a 32 bytes length
MD5 hash which is iterated twice. It seems that the existing
documentation on this function is incorrect. It would be nice if we
would know what exact algorithm is used to calculate the 32 bytes
version, since in theory an MD5 hash can never result in a 32 byte
length.

This is our C# code:

PasswordDeriveBytes pdb =
new PasswordDeriveBytes("secretkey",
Encoding.ASCII.getBytes("*&JHj_JHG"), "MD5", 2);
byte[] hash16bytes = pdb.getBytes(16);
byte[] hash32bytes = pdb.getBytes(32);
and results are:

For 16 bytes:

59 192 53 176 173 34 125 34 236 243 119 17 31 99 147 180

For 32 bytes:

115 229 92 88 209 121 109 87 144 35 48 70 22 39 222 198
159 230 239 240 3 64 182 168 91 39 214 244 54 200 89 222
So how is the 32 bytes result calculated?

Thanks,

rvangeldrop





Reply With Quote
  #6  
Old   
Dominick Baier
 
Posts: n/a

Default Re: Exact implementation of PasswordDerivedBytes - 07-30-2007 , 11:38 AM



well - since i am not working for microsoft

a) i can't give you the source code
b) i don't set any expectations
c) i don't care about your partner status

but a quick google for reflector (http://www.google.de/search?q=reflector)
would reveal a very useful tool with which you can look at the implementation
yourself.

HTH.


-----
Dominick Baier (http://www.leastprivilege.com)

Developing More Secure Microsoft ASP.NET 2.0 Applications (http://www.microsoft.com/mspress/books/9989.asp)

Quote:
Hi Dominick,

This is obviously not the kind of answer I am expecting.

1. Can you explain me in more detail what 'reflector' is and how I can
use it?

2. Maybe it is easier to give me the code inside PasswordDeriveBytes,
since with other similar situations I'm used to being helped that way.
We are a Gold Certified Partner so I was guessing I'm entitled to a
more service-oriented answer.

This answer is also very disappointing since the documentation
Microsoft is already providing on this subject is incorrect: "This
class uses an extension of the PBKDF1 algorithm defined in the PKCS#5
v2.0 standard to derive bytes suitable for use as key material from a
password. The standard is documented in IETF RRC 2898." see also:

http://msdn2.microsoft.com/en-us/lib...y.cryptography.
passwordderivebytes.aspx

I expect you to help me explain why this incorrect and what the actual
implementation is. If this document would be correct my results would
have been different.

Regards,

rvangeldrop

"Dominick Baier" wrote:

Use reflector.

-----
Dominick Baier (http://www.leastprivilege.com)
Developing More Secure Microsoft ASP.NET 2.0 Applications
(http://www.microsoft.com/mspress/books/9989.asp)

Hello,

We are currently running a project in which we wish to reengineer
parts of the System.Security.Cryptography namespace on a unix
machine.

We discovered that the implementation of the PasswordDerivedBytes
shows some unexpected results in case the input is a 32 bytes length
MD5 hash which is iterated twice. It seems that the existing
documentation on this function is incorrect. It would be nice if we
would know what exact algorithm is used to calculate the 32 bytes
version, since in theory an MD5 hash can never result in a 32 byte
length.

This is our C# code:

PasswordDeriveBytes pdb =
new PasswordDeriveBytes("secretkey",
Encoding.ASCII.getBytes("*&JHj_JHG"), "MD5", 2);
byte[] hash16bytes = pdb.getBytes(16);
byte[] hash32bytes = pdb.getBytes(32);
and results are:
For 16 bytes:

59 192 53 176 173 34 125 34 236 243 119 17 31 99 147 180

For 32 bytes:

115 229 92 88 209 121 109 87 144 35 48 70 22 39 222 198 159 230 239
240 3 64 182 168 91 39 214 244 54 200 89 222 So how is the 32 bytes
result calculated?

Thanks,

rvangeldrop




Reply With Quote
  #7  
Old   
Dominick Baier
 
Posts: n/a

Default Re: Exact implementation of PasswordDerivedBytes - 07-30-2007 , 11:38 AM



well - since i am not working for microsoft

a) i can't give you the source code
b) i don't set any expectations
c) i don't care about your partner status

but a quick google for reflector (http://www.google.de/search?q=reflector)
would reveal a very useful tool with which you can look at the implementation
yourself.

HTH.


-----
Dominick Baier (http://www.leastprivilege.com)

Developing More Secure Microsoft ASP.NET 2.0 Applications (http://www.microsoft.com/mspress/books/9989.asp)

Quote:
Hi Dominick,

This is obviously not the kind of answer I am expecting.

1. Can you explain me in more detail what 'reflector' is and how I can
use it?

2. Maybe it is easier to give me the code inside PasswordDeriveBytes,
since with other similar situations I'm used to being helped that way.
We are a Gold Certified Partner so I was guessing I'm entitled to a
more service-oriented answer.

This answer is also very disappointing since the documentation
Microsoft is already providing on this subject is incorrect: "This
class uses an extension of the PBKDF1 algorithm defined in the PKCS#5
v2.0 standard to derive bytes suitable for use as key material from a
password. The standard is documented in IETF RRC 2898." see also:

http://msdn2.microsoft.com/en-us/lib...y.cryptography.
passwordderivebytes.aspx

I expect you to help me explain why this incorrect and what the actual
implementation is. If this document would be correct my results would
have been different.

Regards,

rvangeldrop

"Dominick Baier" wrote:

Use reflector.

-----
Dominick Baier (http://www.leastprivilege.com)
Developing More Secure Microsoft ASP.NET 2.0 Applications
(http://www.microsoft.com/mspress/books/9989.asp)

Hello,

We are currently running a project in which we wish to reengineer
parts of the System.Security.Cryptography namespace on a unix
machine.

We discovered that the implementation of the PasswordDerivedBytes
shows some unexpected results in case the input is a 32 bytes length
MD5 hash which is iterated twice. It seems that the existing
documentation on this function is incorrect. It would be nice if we
would know what exact algorithm is used to calculate the 32 bytes
version, since in theory an MD5 hash can never result in a 32 byte
length.

This is our C# code:

PasswordDeriveBytes pdb =
new PasswordDeriveBytes("secretkey",
Encoding.ASCII.getBytes("*&JHj_JHG"), "MD5", 2);
byte[] hash16bytes = pdb.getBytes(16);
byte[] hash32bytes = pdb.getBytes(32);
and results are:
For 16 bytes:

59 192 53 176 173 34 125 34 236 243 119 17 31 99 147 180

For 32 bytes:

115 229 92 88 209 121 109 87 144 35 48 70 22 39 222 198 159 230 239
240 3 64 182 168 91 39 214 244 54 200 89 222 So how is the 32 bytes
result calculated?

Thanks,

rvangeldrop




Reply With Quote
  #8  
Old   
=?Utf-8?B?cnZhbmdlbGRyb3A=?=
 
Posts: n/a

Default Re: Exact implementation of PasswordDerivedBytes - 07-30-2007 , 01:18 PM



Hi Dominick,

I'm sorry. I lived under the false impression that these questions were
always answered by MS employees.

Apparently you are some other reader that wanted to help me along quickly. I
hope reflector will help me along, but my expectations are low.

Any clue on how I can get an MS employee to take a look at this?

Kind regards,

rvangeldrop

"Dominick Baier" wrote:

Quote:
well - since i am not working for microsoft

a) i can't give you the source code
b) i don't set any expectations
c) i don't care about your partner status

but a quick google for reflector (http://www.google.de/search?q=reflector)
would reveal a very useful tool with which you can look at the implementation
yourself.

HTH.


-----
Dominick Baier (http://www.leastprivilege.com)

Developing More Secure Microsoft ASP.NET 2.0 Applications (http://www.microsoft.com/mspress/books/9989.asp)

Hi Dominick,

This is obviously not the kind of answer I am expecting.

1. Can you explain me in more detail what 'reflector' is and how I can
use it?

2. Maybe it is easier to give me the code inside PasswordDeriveBytes,
since with other similar situations I'm used to being helped that way.
We are a Gold Certified Partner so I was guessing I'm entitled to a
more service-oriented answer.

This answer is also very disappointing since the documentation
Microsoft is already providing on this subject is incorrect: "This
class uses an extension of the PBKDF1 algorithm defined in the PKCS#5
v2.0 standard to derive bytes suitable for use as key material from a
password. The standard is documented in IETF RRC 2898." see also:

http://msdn2.microsoft.com/en-us/lib...y.cryptography.
passwordderivebytes.aspx

I expect you to help me explain why this incorrect and what the actual
implementation is. If this document would be correct my results would
have been different.

Regards,

rvangeldrop

"Dominick Baier" wrote:

Use reflector.

-----
Dominick Baier (http://www.leastprivilege.com)
Developing More Secure Microsoft ASP.NET 2.0 Applications
(http://www.microsoft.com/mspress/books/9989.asp)

Hello,

We are currently running a project in which we wish to reengineer
parts of the System.Security.Cryptography namespace on a unix
machine.

We discovered that the implementation of the PasswordDerivedBytes
shows some unexpected results in case the input is a 32 bytes length
MD5 hash which is iterated twice. It seems that the existing
documentation on this function is incorrect. It would be nice if we
would know what exact algorithm is used to calculate the 32 bytes
version, since in theory an MD5 hash can never result in a 32 byte
length.

This is our C# code:

PasswordDeriveBytes pdb =
new PasswordDeriveBytes("secretkey",
Encoding.ASCII.getBytes("*&JHj_JHG"), "MD5", 2);
byte[] hash16bytes = pdb.getBytes(16);
byte[] hash32bytes = pdb.getBytes(32);
and results are:
For 16 bytes:

59 192 53 176 173 34 125 34 236 243 119 17 31 99 147 180

For 32 bytes:

115 229 92 88 209 121 109 87 144 35 48 70 22 39 222 198 159 230 239
240 3 64 182 168 91 39 214 244 54 200 89 222 So how is the 32 bytes
result calculated?

Thanks,

rvangeldrop





Reply With Quote
  #9  
Old   
=?Utf-8?B?cnZhbmdlbGRyb3A=?=
 
Posts: n/a

Default Re: Exact implementation of PasswordDerivedBytes - 07-30-2007 , 01:18 PM



Hi Dominick,

I'm sorry. I lived under the false impression that these questions were
always answered by MS employees.

Apparently you are some other reader that wanted to help me along quickly. I
hope reflector will help me along, but my expectations are low.

Any clue on how I can get an MS employee to take a look at this?

Kind regards,

rvangeldrop

"Dominick Baier" wrote:

Quote:
well - since i am not working for microsoft

a) i can't give you the source code
b) i don't set any expectations
c) i don't care about your partner status

but a quick google for reflector (http://www.google.de/search?q=reflector)
would reveal a very useful tool with which you can look at the implementation
yourself.

HTH.


-----
Dominick Baier (http://www.leastprivilege.com)

Developing More Secure Microsoft ASP.NET 2.0 Applications (http://www.microsoft.com/mspress/books/9989.asp)

Hi Dominick,

This is obviously not the kind of answer I am expecting.

1. Can you explain me in more detail what 'reflector' is and how I can
use it?

2. Maybe it is easier to give me the code inside PasswordDeriveBytes,
since with other similar situations I'm used to being helped that way.
We are a Gold Certified Partner so I was guessing I'm entitled to a
more service-oriented answer.

This answer is also very disappointing since the documentation
Microsoft is already providing on this subject is incorrect: "This
class uses an extension of the PBKDF1 algorithm defined in the PKCS#5
v2.0 standard to derive bytes suitable for use as key material from a
password. The standard is documented in IETF RRC 2898." see also:

http://msdn2.microsoft.com/en-us/lib...y.cryptography.
passwordderivebytes.aspx

I expect you to help me explain why this incorrect and what the actual
implementation is. If this document would be correct my results would
have been different.

Regards,

rvangeldrop

"Dominick Baier" wrote:

Use reflector.

-----
Dominick Baier (http://www.leastprivilege.com)
Developing More Secure Microsoft ASP.NET 2.0 Applications
(http://www.microsoft.com/mspress/books/9989.asp)

Hello,

We are currently running a project in which we wish to reengineer
parts of the System.Security.Cryptography namespace on a unix
machine.

We discovered that the implementation of the PasswordDerivedBytes
shows some unexpected results in case the input is a 32 bytes length
MD5 hash which is iterated twice. It seems that the existing
documentation on this function is incorrect. It would be nice if we
would know what exact algorithm is used to calculate the 32 bytes
version, since in theory an MD5 hash can never result in a 32 byte
length.

This is our C# code:

PasswordDeriveBytes pdb =
new PasswordDeriveBytes("secretkey",
Encoding.ASCII.getBytes("*&JHj_JHG"), "MD5", 2);
byte[] hash16bytes = pdb.getBytes(16);
byte[] hash32bytes = pdb.getBytes(32);
and results are:
For 16 bytes:

59 192 53 176 173 34 125 34 236 243 119 17 31 99 147 180

For 32 bytes:

115 229 92 88 209 121 109 87 144 35 48 70 22 39 222 198 159 230 239
240 3 64 182 168 91 39 214 244 54 200 89 222 So how is the 32 bytes
result calculated?

Thanks,

rvangeldrop





Reply With Quote
  #10  
Old   
Joe Kaplan
 
Posts: n/a

Default Re: Exact implementation of PasswordDerivedBytes - 07-30-2007 , 03:36 PM



Typically, MS support only answers questions that are posted with registered
newsgroup aliases (a discussions.microsoft.com email address).

Joe K.
--
Joe Kaplan-MS MVP Directory Services Programming
Co-author of "The .NET Developer's Guide to Directory Services Programming"
http://www.directoryprogramming.net
--
"rvangeldrop" <rvangeldrop (AT) discussions (DOT) microsoft.com> wrote

Quote:
Hi Dominick,

I'm sorry. I lived under the false impression that these questions were
always answered by MS employees.

Apparently you are some other reader that wanted to help me along quickly.
I
hope reflector will help me along, but my expectations are low.

Any clue on how I can get an MS employee to take a look at this?

Kind regards,

rvangeldrop

"Dominick Baier" wrote:

well - since i am not working for microsoft

a) i can't give you the source code
b) i don't set any expectations
c) i don't care about your partner status

but a quick google for reflector
(http://www.google.de/search?q=reflector)
would reveal a very useful tool with which you can look at the
implementation
yourself.

HTH.


-----
Dominick Baier (http://www.leastprivilege.com)

Developing More Secure Microsoft ASP.NET 2.0 Applications
(http://www.microsoft.com/mspress/books/9989.asp)

Hi Dominick,

This is obviously not the kind of answer I am expecting.

1. Can you explain me in more detail what 'reflector' is and how I can
use it?

2. Maybe it is easier to give me the code inside PasswordDeriveBytes,
since with other similar situations I'm used to being helped that way.
We are a Gold Certified Partner so I was guessing I'm entitled to a
more service-oriented answer.

This answer is also very disappointing since the documentation
Microsoft is already providing on this subject is incorrect: "This
class uses an extension of the PBKDF1 algorithm defined in the PKCS#5
v2.0 standard to derive bytes suitable for use as key material from a
password. The standard is documented in IETF RRC 2898." see also:

http://msdn2.microsoft.com/en-us/lib...y.cryptography.
passwordderivebytes.aspx

I expect you to help me explain why this incorrect and what the actual
implementation is. If this document would be correct my results would
have been different.

Regards,

rvangeldrop

"Dominick Baier" wrote:

Use reflector.

-----
Dominick Baier (http://www.leastprivilege.com)
Developing More Secure Microsoft ASP.NET 2.0 Applications
(http://www.microsoft.com/mspress/books/9989.asp)

Hello,

We are currently running a project in which we wish to reengineer
parts of the System.Security.Cryptography namespace on a unix
machine.

We discovered that the implementation of the PasswordDerivedBytes
shows some unexpected results in case the input is a 32 bytes length
MD5 hash which is iterated twice. It seems that the existing
documentation on this function is incorrect. It would be nice if we
would know what exact algorithm is used to calculate the 32 bytes
version, since in theory an MD5 hash can never result in a 32 byte
length.

This is our C# code:

PasswordDeriveBytes pdb =
new PasswordDeriveBytes("secretkey",
Encoding.ASCII.getBytes("*&JHj_JHG"), "MD5", 2);
byte[] hash16bytes = pdb.getBytes(16);
byte[] hash32bytes = pdb.getBytes(32);
and results are:
For 16 bytes:

59 192 53 176 173 34 125 34 236 243 119 17 31 99 147 180

For 32 bytes:

115 229 92 88 209 121 109 87 144 35 48 70 22 39 222 198 159 230 239
240 3 64 182 168 91 39 214 244 54 200 89 222 So how is the 32 bytes
result calculated?

Thanks,

rvangeldrop







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